find the slope and give equation of the line that goes through the points (3,9) and (-2,9)
slope is 0, correct? what's the next part?
equation of slope of a line is\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
here\[x _{1}=3,y _{1}=9,x _{2}=-2,y _{2}=9\]
So what you do it connect them together
(9 - 9) / (3 - - 2) = 0 / 5 = 0
Am I supposed to give the answers on this website, or just hints?
ya
you can give answer
0 for slope is what i got...
same here
and the equation of line will b\[y-y _{1}=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }(x-x _{1})\]
just plug in those values in this equation
plug in the coordinates to that equation?
ya
write the result u got after calculation
Given points are (3,9) and (-2,9) i.e. x1= 3, x2= -2, y1= 9, y2= 9 \[Slope (m) = \frac{ y _{2} -y _{1}}{ x _{2} -x _{1} }=\frac{ 9 -9}{ -2 -3 }=\frac{ 0}{ -5 }=0\] Now Eq of line passing through two points is given as: \[y-{y _{1}}=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }(x-{x _{1}})\rightarrow y-9=0(x-3)\rightarrow y-9=0 \] i.e. y=9 is the required eq of the given points of line.
ok, that's what i got...so it would be y=9
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