Question

Calculate the energy needed to change 200.0 g of ice from -15.0° C to water at 10.0° C.

Answer 1

Besides heat required for increase in temperature of ice(water) ,we also need heat for changing state from ice at 0 degrees to water at 0 degrees.

So heat required = ΔT*s*m + mL

ΔT=25
m=0.2kg
s=specific heat capacity of water (or ice) = 4186 J/Kg/K
L=Latent heat of water =334000 J/kg

Answer 2

So would my equation be..
\[(25 \times 4186 \times 0.2) + (0.2 \times 334000)\]

Answer 3

Yes.

Answer 4

So my answer would be 87,730?

Answer 5

Yes.

Answer 6

thank you