A ball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. If it is dropped from this height, what will be the kinetic energy of the ball when it reaches 1.5 meters above the ground?
@chmvijay
So can you first find the potential energy at this height ?
As the object falls the potential energy is converted to kinetic energy
since no external force is being applied on the object, the energy of the object is conserved. use the law of conservation of energy to calculate the kinetic energy.
im still a little lost? :l
what do you get for the potential energy at before the ball falls ?
Okay @UnkleRhaukus in order to find PE i need the acceleration due to gravity right?
yeah it should be about 9.8 m/s^2
(assuming your on earth)
How did you get that?
On the surface of earth acceleration due to gravity is about 9.8 m/s^2
oh okay so now i just calculate?
Wait, i look for PE first or the KE?o.o
First, find the Potential energy before the object is dropped. then, find the potential energy at 1.5 meters above the ground The difference is the energy that has gone to kinetic energy
Okay before the ball is dropped it will be 6.37meters/second if im not mistaking
yes,
And then do i add 1.5 or subtract it from the given hieght?
but the units for energy is kg m^2 /s^2 or J
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