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Mathematics 15 Online
OpenStudy (anonymous):

Find the coordinates of quadrilateral PQRS with vertices P(1,4) Q(-1,4) R(-2,-4) S(2,-4) under the translation (z,y) ---> (x-5,y+3) PLEASE HELP

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

(x,y) ---> (x-5,y+3) means that you take any point (x,y) and shift it 5 units left and 3 units up

jimthompson5910 (jim_thompson5910):

so in the case of point P we know that x = 1 and y = 4 x ---> x - 5 so plug in x = 1 to get x-5 = 1-5 = -4 y ---> y+3 plug in y = 4 to get y +3 = 4+3 = 7 in the end, P(1,4) translates to P ' (-4, 7)

OpenStudy (anonymous):

Thank you! and one more I am having trouble with @jim_thompson5910

jimthompson5910 (jim_thompson5910):

fill in the blank for the x coordinates in point X and X' 5 + ______ = 3

OpenStudy (anonymous):

-2 ? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

so x ---> x-2

jimthompson5910 (jim_thompson5910):

fill in the blank for the y coordinates of X ---> X' 4 + _____ = 1

OpenStudy (anonymous):

-3

jimthompson5910 (jim_thompson5910):

y ---> y-3

jimthompson5910 (jim_thompson5910):

the rule is (x,y) ----> (x-2, y-3)

jimthompson5910 (jim_thompson5910):

is that enough to find Y ' and Z ' ?

OpenStudy (anonymous):

Is it b? like I know I have -2 , y-3 but what do i do with those ?

jimthompson5910 (jim_thompson5910):

x-2 means you subtract 2 from the x coordinate

jimthompson5910 (jim_thompson5910):

so because the x coordinate of point Y is 3, we know that x-2 = 3-2 = 1

jimthompson5910 (jim_thompson5910):

so the x coordinate of Y ' is 1

OpenStudy (anonymous):

okay thank you!! @jim_thompson5910 and sorry I ask you so much...

jimthompson5910 (jim_thompson5910):

no it's good you ask questions

jimthompson5910 (jim_thompson5910):

the key is that you ideally learn from them and from there you can do it on your own eventually, but I'm sure you are very smart and can handle it

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