Find the coordinates of quadrilateral PQRS with vertices P(1,4) Q(-1,4) R(-2,-4) S(2,-4) under the translation (z,y) ---> (x-5,y+3) PLEASE HELP
(x,y) ---> (x-5,y+3) means that you take any point (x,y) and shift it 5 units left and 3 units up
so in the case of point P we know that x = 1 and y = 4 x ---> x - 5 so plug in x = 1 to get x-5 = 1-5 = -4 y ---> y+3 plug in y = 4 to get y +3 = 4+3 = 7 in the end, P(1,4) translates to P ' (-4, 7)
Thank you! and one more I am having trouble with @jim_thompson5910
fill in the blank for the x coordinates in point X and X' 5 + ______ = 3
-2 ? @jim_thompson5910
so x ---> x-2
fill in the blank for the y coordinates of X ---> X' 4 + _____ = 1
-3
y ---> y-3
the rule is (x,y) ----> (x-2, y-3)
is that enough to find Y ' and Z ' ?
Is it b? like I know I have -2 , y-3 but what do i do with those ?
x-2 means you subtract 2 from the x coordinate
so because the x coordinate of point Y is 3, we know that x-2 = 3-2 = 1
so the x coordinate of Y ' is 1
okay thank you!! @jim_thompson5910 and sorry I ask you so much...
no it's good you ask questions
the key is that you ideally learn from them and from there you can do it on your own eventually, but I'm sure you are very smart and can handle it
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