Question

Really quick question. Where did the 1/81 come from..

Answer 1

Ah. what is your x-value? the thing you used to sub.

Answer 2

\[x=3\sin (\theta)\]

Answer 3

\[\large \int\limits\frac{1}{x^4\sqrt{9-x^2}}dx\]\[\large \sqrt{9-x^2} : x= 3\sin(\theta)\]\[\large dx = 3\cos(\theta)d(\theta)\]

Answer 4

ok, so if you have your value of x.. then \(\large (3\sin(\theta))^4\) = \(\large 81\sin^4(\theta)\)

Answer 5

lol smh

Answer 6

there you go! :)

Answer 7

wow... I need to get to bed. Thanks lol

Answer 8

Hahaha no problem.

Answer 9

And thank you :D

Answer 10

:)

Answer 11

you're welcome, Ms. Jhannybean