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Algebra 13 Online
OpenStudy (anonymous):

(2x-6)(3x^2-3x-6)

OpenStudy (skullpatrol):

Any ideas?

OpenStudy (anonymous):

you mean like the options?

OpenStudy (skullpatrol):

I mean any idea on how you would multiply them?

OpenStudy (anonymous):

yea like you have to distribute them together

OpenStudy (anonymous):

like 2x*3x^2

OpenStudy (skullpatrol):

Good, that's the idea: a(b + c) = ab + ac

OpenStudy (skullpatrol):

$$(2x-6)(3x^2-3x-6) $$ $$=(2x-6)(3x^2) +(2x-6)(-3x)+(2x-6)(-6)$$

OpenStudy (anonymous):

ok then you simplify it right?

OpenStudy (skullpatrol):

Yes, first finish multiplying it out.

OpenStudy (anonymous):

ok so the first will be 6 then 24 then 6 then 36

OpenStudy (anonymous):

But what I don't get is the negative symbols and all that

OpenStudy (loser66):

what do you mean by you don't know the negative symbols? (-2) *2=? (-2)*(-3)=? (-2)*(-3)*(-4)=?

OpenStudy (anonymous):

6x^3-24x62+6x+36

OpenStudy (loser66):

yup

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