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Algebra
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(2x-6)(3x^2-3x-6)
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Any ideas?
you mean like the options?
I mean any idea on how you would multiply them?
yea like you have to distribute them together
like 2x*3x^2
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Good, that's the idea: a(b + c) = ab + ac
$$(2x-6)(3x^2-3x-6) $$ $$=(2x-6)(3x^2) +(2x-6)(-3x)+(2x-6)(-6)$$
ok then you simplify it right?
Yes, first finish multiplying it out.
ok so the first will be 6 then 24 then 6 then 36
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But what I don't get is the negative symbols and all that
what do you mean by you don't know the negative symbols? (-2) *2=? (-2)*(-3)=? (-2)*(-3)*(-4)=?
6x^3-24x62+6x+36
yup
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