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OpenStudy (anonymous):
12
OpenStudy (anonymous):
thank you :)
OpenStudy (anonymous):
welcome
OpenStudy (anonymous):
@ganeshie8 Help?
ganeshie8 (ganeshie8):
il give a hint, see if it helps :)
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ganeshie8 (ganeshie8):
15 = 45-30
OpenStudy (anonymous):
hmmm?
OpenStudy (anonymous):
its equal?
OpenStudy (anonymous):
@ganeshie8 you look so much like your mom in that picture
ganeshie8 (ganeshie8):
\(120 \cos (15)\)
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ganeshie8 (ganeshie8):
\(120 \cos (45 - 30)\)
OpenStudy (anonymous):
69
ganeshie8 (ganeshie8):
use the cosine difference formula
ganeshie8 (ganeshie8):
\(\cos(A-B) = \cos A \cos B + \sin A \sin B\)
OpenStudy (anonymous):
Okay let me see
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OpenStudy (anonymous):
is it -7.5?
OpenStudy (anonymous):
A biker rides on an upward-sloped road inclined at a 15.0° angle with the horizontal. If he moves at a constant speed of 2.0 meters/second for 60 seconds, what is the magnitude of his horizontal displacement?
Thats my problem?
OpenStudy (anonymous):
im lost...
ganeshie8 (ganeshie8):
oh I see... you're right ! horizontal displacement = 120 cos 15
ganeshie8 (ganeshie8):
you dont wanto use calculator is it ?
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OpenStudy (anonymous):
but none of my answers match/:
OpenStudy (anonymous):
wait what? sorry
ganeshie8 (ganeshie8):
list your options, we will see
OpenStudy (anonymous):
A. 3 meters
B. 116 meters
C. 60 meters
D. 130 meters
ganeshie8 (ganeshie8):
im getting the answer as 116 meters.
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ganeshie8 (ganeshie8):
you're not allowed to use calculator to solve this is it ?