Which value(s) must be excluded from solutions for this equation?
2/x^2-1 = 3/x+1 + 4/x-1

Question

Which value(s) must be excluded from solutions for this equation? 
2/x^2-1 = 3/x+1 + 4/x-1

anonymous · Answer

-1 and +1

this is because the denominators can never equal 0, because we cannot divide by zero.

the denominators here are x^1-1, x+1, x-1

anonymous · Answer

Well one of the answers is indeed 0, so why wouldn't I choose that?

anonymous · Answer

@robz8

lopezking1 · Answer

2/ x^2-1 = 3/x+1 + 4/ x-1
2/(x^2-1) = (3x- 3 + 4x +4) / (x+1)(x-1)
2/(x^2-1) = (7x + 1) / (x^2 - 1)
2 = 7x +1
x= 1/7, (substitute the value, if the equation is not satisfied then x is not equal to 1/7)

lopezking1 · Answer

@Cubi-Cal

anonymous · Answer

But I'm confused, the given answers are -1, 0, -1 and 1, or 1. @lopezking1

lopezking1 · Answer

Ohh well then in this case it would be 0 i think

anonymous · Answer

Thanks!c:

lopezking1 · Answer

Np