Question

Find the distance between (1, -2) and (-4, 3).

Answer 1

so find hypotenuse
\[h^2 = a^2 + b^2 \]

Answer 2

so find hypotenuse @mmholmes

Answer 3

im not sure how.

Answer 4

\[d=\sqrt{(x _{_{1}}-x _{2})^2+(y _{1}-y _{2})^2}\]

(1, -2) and (-4, 3)
(x1,y1) and (x2,y2)
x1=1
x2=-4
y1=-2
y2=3

\[d=\sqrt{(1+4)^2+(-2-3)^2}\]

\[d=\sqrt{(5)^2+(-5)^2}\]

\[d=\sqrt{50}\]

\[d=5\sqrt{2}\]

Answer 5

@mmholmes just do whaat nurali did lol
huge effort there dude @Nurali !

Answer 6

@mmholmes how'd jew go? understand ok? need clarification?

Answer 7

is the answer 5?

Answer 8

so 25?