David has $1.05 in dimes and quarters. How many combinations of coins could he have? A. 1 B. 2 C. 3 D. 5
Can anybody explain how to solve this?
1 dime is worth 10 cents. 1 quarter is worth 25 cents. You can guess and check. If David have 1 quarter, how many dimes would he have?
2 ?
Well yes. The answer is 2. You can think logically as well. A quarter is worth 25 cents, and a dime is worth 10 cents. A quarter can only end in 5 or 0, while a dime only end in 0. So if you have 1 quarter, the you would have 8 dimes. There's no possible outcome with 2 quarters because .25+.25= .50, and that end in 0. The total amount has a .05. So the total amount of quarter must end in odd. But .25*5 is over 1.05. So there must be less than 5 quarters. Do you understand now? I hope this help!
@GoldPhenoix I understand what you wrote, but I don't know what the answer would be
The answer is 2.
Thanks!!!
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