Algebra
18 Online
OpenStudy (anonymous):
you select a card a random without replacing the card you select a second card find the probability P(M, then H)
Mathemtics
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OpenStudy (anonymous):
1/55
OpenStudy (kirbykirby):
what's M for?
OpenStudy (anonymous):
I'm trying to figure out how they got the answer
I'm not really looking for answers to the problems. But someone to help me with the equation
OpenStudy (anonymous):
P(M, then H) = P(M) x P(H) =(2/7) x( 1/6 )= ?
^ ^
| only 1 card with letter H
There are 2 cards with letter M
OpenStudy (kirbykirby):
what does the "M" stand for?
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OpenStudy (anonymous):
Mathematics
OpenStudy (kirbykirby):
Mathematics card? What kind of deck of cards are you using?
OpenStudy (anonymous):
yes mathematics cards
I'm Sorry
OpenStudy (kirbykirby):
I don;t understand what kind of cards these are lol sorry.
OpenStudy (anonymous):
its on one of my math tests
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OpenStudy (anonymous):
and the full question is
OpenStudy (anonymous):
you select a card at random. without replacing the card you select a second card find the probability'
MATHEMATICS
OpenStudy (kirbykirby):
oh the cards are the letters forming the word 'Mathematics' ?
OpenStudy (anonymous):
P(M,THEN H)
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
I don't know how they got 1/55
OpenStudy (kirbykirby):
Ok got it :)
OpenStudy (kirbykirby):
\[\frac{2}{11}*\frac{1}{10}\]
OpenStudy (kirbykirby):
You have 2 'M" out of 11 letters, so to get an M on the first turn, you have a probability of 2/11
OpenStudy (anonymous):
Ok I see now.
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OpenStudy (anonymous):
so then you don't replace the card
OpenStudy (anonymous):
that makes H for the 1 out of 10. Right?
OpenStudy (kirbykirby):
yes exactly :)
OpenStudy (anonymous):
Thank You very Much
OpenStudy (kirbykirby):
yw