Mathematics
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OpenStudy (anonymous):
help please
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OpenStudy (anonymous):
OpenStudy (bahrom7893):
Look up the equation of a circle and post it here.
OpenStudy (anonymous):
(x-h)^2+(y-k)^2=r^2
OpenStudy (bahrom7893):
Yes. What are h and k?
OpenStudy (anonymous):
2 and 6?
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OpenStudy (bahrom7893):
yup
OpenStudy (anonymous):
ok what do i do know
OpenStudy (bahrom7893):
well for starters, replace h and k with 2 and 6 and post what you get.
OpenStudy (anonymous):
(2-6)^2+(y-k)^2=r^2
OpenStudy (bahrom7893):
no you replace x and h, you need to replace h and k
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OpenStudy (rmrjr22):
h,k are center points
OpenStudy (bahrom7893):
*replaced
OpenStudy (anonymous):
6-2?
OpenStudy (bahrom7893):
Can you look at the equation and put the correct values instead of h and k?
OpenStudy (rmrjr22):
no.... this is ur formula ((x-h)^2+(y-k)^2=r^2)... plug in the center of the circle points to (h,k) respectfully
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OpenStudy (anonymous):
ooooo ok
OpenStudy (anonymous):
(x-2)^2+(y-6)^2=r^2
OpenStudy (bahrom7893):
Yes. Now what is r?
OpenStudy (anonymous):
4
OpenStudy (bahrom7893):
Yes, plug that in instead of r
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OpenStudy (rmrjr22):
if you plug that in, what does the finished equation look like?
OpenStudy (anonymous):
(x-2)^2+(y-6)=4^2
OpenStudy (rmrjr22):
bingo, you have ur answer
OpenStudy (anonymous):
omg yayyy
OpenStudy (rmrjr22):
u forgot the ^2 on ur second half
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OpenStudy (anonymous):
o yea i noticed
OpenStudy (rmrjr22):
just remember if you have a center point it will always = (h,k)... just like any other points beside center points on a circle = (x,y)
OpenStudy (anonymous):
thank you so much @bahrom7893 and @rmrjr22
OpenStudy (bahrom7893):
You're very welcome :)