Write the explicit formula for the geometric sequence. a1 = -5 a2 = 20 a3 = -80 A. an = -5 • (-4)n B. an = -5(-4)n-1 C. an = -4(-5)n-1 D. an = -5 • (4)n
Just waiting for some help.........
\(\huge {a _{n} = a _{1}.r^{n-1}}\)
see, \(\huge a _{1} = -5 \) find \(\huge r\) :))
\(\huge r=\frac{ a _{2} }{ a _{1} }\)
So that would be \[\frac{ 5^{_{2}} }{ 5_{1} }\]
no, see \(\huge a _{2} = 20 \) :D
So \[\frac{ 20 }{ 10 } then?\]
\(\huge a _{1} = -5 \) \(\huge r=\frac{ 20 }{ -5 }\)
So we got r, where do I go from there?
\(\huge {a _{n} = a _{1}.r^{n-1}}\) you will find \(\huge a _{n}\) by your \(\huge r\) :))
I don't know how to solve that.
whats your \(\huge r \) ?
20/-5
Whats the result of it?
i mean 20/-5= ?
-4?
Yes, then an= -5.(-4)^n-1
Thank you very much
hope you understand :)
an = a1 * r ^ n - 1 r = the difference between each term....what you multiply by to get the next number a1 = the first number
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