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Mathematics 18 Online
OpenStudy (anonymous):

@rmrjr22 can you help me with e few more i really need the help?

OpenStudy (rmrjr22):

lets try

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

Choose the correct description of the graph of the inequality x<= 3 Open circle on 3, shading to the left. Closed circle on 3, shading to the left. Open circle on 3, shading to the right. Closed circle on 3, shading to the right.

OpenStudy (rmrjr22):

whats the direction of the inequality?

OpenStudy (rmrjr22):

hint ( <,>)

OpenStudy (anonymous):

the right

OpenStudy (rmrjr22):

which way is it pointing?

OpenStudy (anonymous):

left

OpenStudy (anonymous):

sorry

OpenStudy (rmrjr22):

when you graph x = 3, what are the co-ordinates?

OpenStudy (anonymous):

im doing a test so im in a hurry

OpenStudy (anonymous):

3/1

OpenStudy (rmrjr22):

(3,0) from there its a vertical line right?

OpenStudy (anonymous):

ok

OpenStudy (rmrjr22):

then just look at where the arrow is pointing and you have the direction of shading

OpenStudy (anonymous):

the left

OpenStudy (rmrjr22):

good, now is it open or closed?

OpenStudy (rmrjr22):

Open circles= greater than or less than Closed circles=greater than or equal to, less than or equal to, and the equal sign

OpenStudy (anonymous):

opem

OpenStudy (anonymous):

so its a

OpenStudy (rmrjr22):

u said x <= 3 right?

OpenStudy (anonymous):

yea

OpenStudy (rmrjr22):

Closed circles=greater than or equal to, less than or equal to, and the equal sign

OpenStudy (anonymous):

so what would it be

OpenStudy (rmrjr22):

b

OpenStudy (anonymous):

ok thanks i have another

OpenStudy (rmrjr22):

anything with an equal sign with inequality is a closed circle

OpenStudy (anonymous):

Choose the correct description of the graph of the inequality -2x < 10. Open circle on -5, shading to the left. Closed circle on -5, shading to the left. Open circle on -5, shading to the right. Closed circle on -5, shading to the right.

OpenStudy (anonymous):

so woulf this be d

OpenStudy (rmrjr22):

get x alone

OpenStudy (anonymous):

thats what i did

OpenStudy (rmrjr22):

so u end up with x<-5 or x>-5?

OpenStudy (rmrjr22):

?

OpenStudy (anonymous):

x<-5

OpenStudy (rmrjr22):

x> -5 is the correct one

OpenStudy (rmrjr22):

when you divide over to the otherside, it switches the sign

OpenStudy (anonymous):

so that would be??

OpenStudy (rmrjr22):

i cant give direct answers, but what i just gave you is more than enough to find the answer

OpenStudy (anonymous):

ok

OpenStudy (rmrjr22):

no = sign.. so it means that its an open circle the arrow is pointing which way?

OpenStudy (rmrjr22):

3rd choice should suffice

OpenStudy (anonymous):

would it be Open circle on -5, shading to the left.

OpenStudy (rmrjr22):

to the right, remember the sign switched over cause of division

OpenStudy (anonymous):

oh yea

OpenStudy (anonymous):

Solve the inequality 2x + 8 < 5x - 4

OpenStudy (rmrjr22):

u want to get x alone

OpenStudy (rmrjr22):

how would u do that?

OpenStudy (anonymous):

i know

OpenStudy (rmrjr22):

12<3x.... did you get that?

OpenStudy (anonymous):

yes

OpenStudy (rmrjr22):

now get x alone, remove the 3

OpenStudy (anonymous):

4<x

OpenStudy (rmrjr22):

good... now last part

OpenStudy (rmrjr22):

remember, when you divide over the symbol <, it switches over

OpenStudy (rmrjr22):

so it becomes 4>x

OpenStudy (anonymous):

x>4

OpenStudy (rmrjr22):

4>x

OpenStudy (rmrjr22):

4 (is greater than) x

OpenStudy (rmrjr22):

shading to the right as an open circle

OpenStudy (anonymous):

x > 4 x > 1 x < 1 x < 4 these are the answers

OpenStudy (rmrjr22):

x < 4 = 4>x

OpenStudy (anonymous):

d

OpenStudy (rmrjr22):

you understand it?

OpenStudy (anonymous):

yea so d is right

OpenStudy (rmrjr22):

yes

OpenStudy (anonymous):

Which of the following is not a way to represent the solution of the inequality 2x - 2 4? 3 x x 3 A number line with a closed circle on 3 and shading to the right. A number line with a closed circle on 3 and shading to the left.

OpenStudy (anonymous):

3>=x x<=3

OpenStudy (rmrjr22):

open up a new one?

OpenStudy (rmrjr22):

2x-24?`

OpenStudy (anonymous):

no i just corrected them

OpenStudy (rmrjr22):

last one

OpenStudy (rmrjr22):

get it?

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