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Mathematics 13 Online
OpenStudy (anonymous):

What is the simplified form of the expression?

OpenStudy (anonymous):

OpenStudy (anonymous):

Exponent laws; do you know them?

OpenStudy (anonymous):

Unfamiliar

OpenStudy (rmrjr22):

im assuming a...

OpenStudy (anonymous):

Thanks

OpenStudy (whpalmer4):

\[k^3(k^{\frac{7}{5}})^{-5}\] \[(x^n)^m = x^{n*m}\] \[k^3(k^\frac{7}{5})^{-5} = k^3k^{\frac{7}{5}*(-5)} = k^3k^{-7} = k^{3-7} = k^{-4} =\frac{1}{k^4}\]

OpenStudy (whpalmer4):

here's a set of exponent laws that are handy: \[x^n*x^m = x^{n+m}\]\[x^n/x^m = x^{n-m}\]\[(ab)^n = a^nb^n\]\[x^{-n} = 1/x^n\]

OpenStudy (anonymous):

Thank you very much

OpenStudy (whpalmer4):

practice them until they are automatic!

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