What is the value of x rounded to the nearest hundredth?
Have you considered the Tangent Function?
i dont know how to do it :/
Why? You should not be given a problem with no tools to solve it. You should have this: \(\tan(\alpha) = \dfrac{Opposite}{Adjacent}\) You should have this: \(\cos(\alpha) = \dfrac{Adjacent}{Hypotenuse}\) You should have this: \(\sin(\alpha) = \dfrac{Opposite}{Hypotenuse}\) Do you have these definitions? This brings to mind that I must have been sleeping when I said "Tangent". Sine would be the right one. Sorry about that.
ok so.. sin49=x/55?
Perfect. Now what?
im not sure
to solve for x you would multiply both sides by 55?
Since 49º is not a convenient number, you'll just need a calculator that can do it.
Yes, multiplying by 55 will solve for x, but you still need a numerical value for \(\sin(49º)\).
how do i get t?
Do you have a calculator with a "sin()" button? There are plenty online calculators. Here's one: http://web2.0calc.com/ There are many more.
so do i put in sin(49) and see what it gives me?
Yes. If you get -0.953752652 then you have to do something else. That is a possible incorrect answer if you are not familiar with your calculator.
i got 41.509
Excellent. One more thing. We have not quite answered the question. What are we missing?
im not sure?
What are the rounding requirements?
to the nearest hundredth ...so its..41...im not sure
41.509 is rounded to thousandths. 41.51 is rounded to hundreths.
ok i see
NOW it's done. Good work.
thank you very much for being so patient with me :)
No worries. It's what we try to do around here.
:)
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