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diff -3x/x^2
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differentiate?
yes please, i'm stuck on this step :/
i know you can simplify to -3/x
\[\large f(x) = \frac{-3x}{x^2}\] use the quotient rule.
ok thanks
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no problem. \[\large D_{x} (f(x)) = D_{x}\left(-\frac{3x}{x^2}\right)\] \[\large \frac{\frac{d}{dx}(-3x)\cdot (x^2) -\frac{d}{dx}(x^2)\cdot (-3x)}{(x^2)^2}\] another way is just to use the power rule after getting rid of the fraction. \[\large -3x(x^{-2})\] and then with this, use the product rule.\[\large f'g + g'f\]\[\large \frac{d}{dx}(-3x)\cdot x^{-2} + \frac{d}{dx} (x^{-2})\cdot (-3x)\]
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