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Mathematics 12 Online
OpenStudy (anonymous):

Eigensvectors and eigensvalue.

OpenStudy (zzr0ck3r):

who Eigen?

OpenStudy (zzr0ck3r):

jk:P

OpenStudy (anonymous):

I have this matrix \[A=\left[\begin{matrix}1 & 2&3 \\ 2 & 4&6\\3&6&9\end{matrix}\right]\] and I need to show that A has the following tree vectors as eigenvectors. In addition to this I have to find the tree eigenvalues.

OpenStudy (zzr0ck3r):

do you know how to find Eigen values?

OpenStudy (zzr0ck3r):

you want these first

OpenStudy (anonymous):

\[v1=\left(\begin{matrix}-2 \\ 1 \\ 0\end{matrix}\right)\] \[v2=\left(\begin{matrix}1 \\ 2 \\ 3\end{matrix}\right)\] \[v3=\left(\begin{matrix}3 \\ 6 \\ -5\end{matrix}\right)\]

OpenStudy (anonymous):

Yes i know have to find the eigenvalues.

OpenStudy (zzr0ck3r):

ok can you give me the latek code you for the matrix to save time...:)

OpenStudy (zzr0ck3r):

\[\begin{matrix}1-a & 2&3 \\ 2 & 4-b&6\\3&6&9-c\end{matrix}\]

OpenStudy (anonymous):

The task says that I must first show that these three are the eigen vector.

OpenStudy (anonymous):

and then find the eigenvalues.

OpenStudy (zzr0ck3r):

ok well you need the Eigen values first Av=ev where e is Eigen values and v is Eigen vectors

OpenStudy (zzr0ck3r):

maybe anther way sec..

OpenStudy (anonymous):

\[Av=\lambda v\]

OpenStudy (zzr0ck3r):

yeah ok, so do Av and it will equal v times a constant

OpenStudy (anonymous):

So I can do it like this?

OpenStudy (zzr0ck3r):

where are you getting [14,28,42]?

OpenStudy (zzr0ck3r):

on the first one av = 0

OpenStudy (anonymous):

Sorry

OpenStudy (zzr0ck3r):

out side of that, yes

OpenStudy (zzr0ck3r):

yep

OpenStudy (zzr0ck3r):

those constants are your eigenvalues

OpenStudy (zzr0ck3r):

so its pretty easy to get the values if you have the vectors, but I don't know of a non guess and check method of getting the vectors without the values...

OpenStudy (zzr0ck3r):

that's prob next in your class...

OpenStudy (anonymous):

So that is enough.

OpenStudy (zzr0ck3r):

yep you found a three vectors such that your matrix times that vector is equal to a constant times that vector

OpenStudy (zzr0ck3r):

so you reduced your matrix to a constant:)

OpenStudy (anonymous):

Thanks..

OpenStudy (zzr0ck3r):

np

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