Eigensvectors and eigensvalue.
who Eigen?
jk:P
I have this matrix \[A=\left[\begin{matrix}1 & 2&3 \\ 2 & 4&6\\3&6&9\end{matrix}\right]\] and I need to show that A has the following tree vectors as eigenvectors. In addition to this I have to find the tree eigenvalues.
do you know how to find Eigen values?
you want these first
\[v1=\left(\begin{matrix}-2 \\ 1 \\ 0\end{matrix}\right)\] \[v2=\left(\begin{matrix}1 \\ 2 \\ 3\end{matrix}\right)\] \[v3=\left(\begin{matrix}3 \\ 6 \\ -5\end{matrix}\right)\]
Yes i know have to find the eigenvalues.
ok can you give me the latek code you for the matrix to save time...:)
\[\begin{matrix}1-a & 2&3 \\ 2 & 4-b&6\\3&6&9-c\end{matrix}\]
The task says that I must first show that these three are the eigen vector.
and then find the eigenvalues.
ok well you need the Eigen values first Av=ev where e is Eigen values and v is Eigen vectors
maybe anther way sec..
\[Av=\lambda v\]
yeah ok, so do Av and it will equal v times a constant
So I can do it like this?
where are you getting [14,28,42]?
on the first one av = 0
Sorry
out side of that, yes
yep
those constants are your eigenvalues
so its pretty easy to get the values if you have the vectors, but I don't know of a non guess and check method of getting the vectors without the values...
that's prob next in your class...
So that is enough.
yep you found a three vectors such that your matrix times that vector is equal to a constant times that vector
so you reduced your matrix to a constant:)
Thanks..
np
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