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Mathematics 9 Online
OpenStudy (anonymous):

simplify (1/(x+2))-(1/x)

OpenStudy (mathstudent55):

is this the problem? |dw:1372429802089:dw|

OpenStudy (mathstudent55):

You are subtracting fractions with different denominators. You need a common denominator. What is the LCD of x + 2 and x?

OpenStudy (anonymous):

x(x+2) or x^2+2x

OpenStudy (anonymous):

both r same

OpenStudy (anonymous):

wats the numerator

OpenStudy (anonymous):

x-(x+2)... so would it just be -2?

OpenStudy (anonymous):

ss correct .... done ..

OpenStudy (mathstudent55):

Good. The LCD is x(x + 2) Now you need to multiply the left fraction by x/x and the right fraction by (x + 2)/(x + 2), so both fractions have the common denominator.

OpenStudy (mathstudent55):

I see you're ahead of me. Yes you're correct.

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