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Verify the identity. sin (x + pi/2) = cos x
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do you know a standard relation for sin (a+b) ?
\(\sin (a+b)=\sin a \cos b +\cos a \sin b\)
just plug in a =x and b =pi/2 there!
what does cos(pi/2) and sin(pi/2) =?
oh, its easy and standard cos (pi/2) = 0 sin (pi/2) = 1
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So I end up with sin x + cos x + sin (1)?
no...show your work, i'll spot you the error
sin(x)cos(pi/2) + cos(x)sin(pi/2) sin(x)cos(0) + cos(x)sin(1) cos(0) = 0 So, sin(x) + cos(x)sin(1) ?
sin(x)cos(pi/2) + cos(x)sin(pi/2) cos pi/2 = 0 , sin pi/2 = 1 sin x (0) + cos x (1) =0+ cos x = cos x got it?!
ask if any doubts...
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Oh!! I feel dumb now. I get it. Aha Thank you!! :)
welcome ^_^
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