What are the solutions of the equation: z2 - 12z + 36 = 0?

A. -6, 6

B. 6, 6

C. 6, -6

D. -6, -6

Question

What are the solutions of the equation: z2 - 12z + 36 = 0? 


A. -6, 6	

B. 6, 6	

C. 6, -6	

D. -6, -6

anonymous · Answer

The first step is to find 2 numbers that when multiplied give you 36 but when added, they give you -12.  Hint: since you have -12 for the sum, the 2 numbers are NEGATIVE.  Start by listing all pairs of numbers that when multiplied give you 36, but where both numbers are NEGATIVE.

explainitlikeimfive · Answer

I do believe it is D.

anonymous · Answer

Good luck to you in all of your studies and thx for the recognition! @ExplainItLikeImFive

anonymous · Answer

It's actually "b"

x^2 - 12x + 36 = 0 = (x - 6)(x - 6)

The "-6" is for finding factors.  The actual zeros are 6,  6.