Find all solutions in the interval (0,2pi). sin^2x + sin x = 0
sin x ( sin x + 1) = 0 sin x = 0 or -1 can u continue from here?
How did you get from the first equation to the second?
sin x is the Greatest common factor of sin^2 x and sin x
so we can take out sin x and divide by sin x to give the quotient in the brackets
this is called factoring
But with that answer you would get pi, 2pi, and 3pi/2. The only options are: x = 0, pi, 4pi/3, 5pi/3 x = 0, pi, pi/3, 2pi/3 x = 0, pi, pi/3, 5pi/3 x = 0, pi, 3pi/2
How did you get from sin x (sin x + 1) = 0 to sin x = 0 or -1 ?
no when sin x = 0 , x = 0 , pi sin x = -1 gives 3pi/2
when 2 functions a and b are multiplied together = 0 then a = 0 or b = 0
Oh, ok. I get it now. I made a simple mistake. Thank you!
yw
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