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Find the thirtieth term of the following sequence. -6, -4, -2, 0, ...
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if you want to do it the easy way... you're adding 2 every term to what is -6 + 12*(2)?
you multiply by 12 because you start with the first term, and you need to find the value 12 terms later for the 13th term
The formula needed for this arithmetic progression is \[n ^{th}\ term=a+(n-1)d\] So the thirtieth term is \[-6+(30-1)2=(2 \times 29)-6\]
i just want the answer im in a exam
it only give this options 52 64 66
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Just calculate the following: \[(2 \times 29)-6=you\ can\ calculate\]
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