Question

Inital-Value Problem: Please check if my solution is right?

Answer 1

k so the ODE of that is right, y = 1/(x^2 + c)

and if y(0) = 1

1 = 1/(0+c)
so c = 1

so the specific solution is y= 1/(x^2 +1)

yeah looks like u did it perfectly!

Answer 2

i got another one. im just taking a picture of it

Answer 3

is this right?

Answer 4

on this third problem. i still dont have a solution coz i dont know how to do this :/

Answer 5

so yeah
ODE = c1 cos x + c2 sin x
if x = 0, sin 0 = 0, cos 0 = 1
so c1 = 1
yep, perfect so far

so yeah, specific solution is y = cos x - 7 sin x
perfect kenji

Answer 6

ur all over this dude!

Answer 7

the third one. i dont know. help?

Answer 8

please help :|

Answer 9

hang on , reading it...

Answer 10

ok

Answer 11

@terenzreignz 1 honestly dont know how to find the solution to that ODE...

Answer 12

@satellite73 @whpalmer4 hey i cath get the 3rd one out, lil help @Nurali @experimentX please?

Answer 13

after u finish sara's question, @tkhunny could u have a look at this please?

Answer 14

On the third. The differential equation is separable and antiderivatives are easily found. Understanding what the question wants is the tricky part.

You do have to be careful with graphing this one. Most graphing programs use logarithms for exponentiation and you will miss things for negative values.

Answer 15

so how would i solve for this one?

Answer 16

i have no idea

Answer 17

You tell me what the problem statement means and we can solve it.

Pick the first quadrant.
Is there a unique solution there?
Given a point in the 1st Quadrant, can you find a solution that hits it?

Answer 18

so how can i solve this :\

Answer 19

hey guys thank for all the help. ill just try this tomorrow @tkhunny . @Jack1 thanks again for the help