Question

|y|=|x| graph please

Answer 1

any attempt ?

Answer 2

you have to take 4 cases, 1 for rach quadrant

Answer 3

each*

Answer 4

i dont understand ?

Answer 5

and yeah i have no idea where to start

Answer 6

\[|y|=\begin{cases}y&\text{for }y\ge0\\-y&\text{for }y<0\end{cases}\]
\[|x|=\begin{cases}x&\text{for }x\ge0\\-x&\text{for }x<0\end{cases}\]
A point in the first quadrant has \(x,y>0\), so \(|y|=y\) and \(|x|=x\).
And so on for the other three quadrants.

Answer 7

i still dont ge tit

Answer 8

In the first quadrant, every point \((x,y)\) is determined by the equation \(|y|=|x|\), which we showed is equivalent to \(y=x\).

Answer 9

In the second quadrant, you have negatives values of \(x\) and positive values of \(y\), which means \(|x|=-x\) and \(|y|=y\), so you every point is determined by the equation \(y=-x\):