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Mathematics 19 Online
OpenStudy (jazzyfa30):

anybody good at polynomials????????????? problems attached

OpenStudy (jazzyfa30):

OpenStudy (jazzyfa30):

please help

OpenStudy (jazzyfa30):

@amistre64 plz help

OpenStudy (anonymous):

2nd one square it 4x^3y*4x^3y

OpenStudy (anonymous):

first one ans is wrong ..

OpenStudy (jazzyfa30):

?????

OpenStudy (jazzyfa30):

@mathkid55 plz help me

OpenStudy (jazzyfa30):

@justinvelarde

OpenStudy (joppei):

arent you supposed to work out a shorter form to write it, in examle the 2nd one. (4x^3y)^2 you can do 4x^3*4x^2 = 4x^5 then do 3y^2 which is 3y^2 and you end up with 4x^5*y^2

OpenStudy (jazzyfa30):

which answer number is that

OpenStudy (joppei):

2

OpenStudy (jazzyfa30):

so number 1 is 2

OpenStudy (joppei):

i don't know if its correct, but it should be the second problem

OpenStudy (jazzyfa30):

ok if you want you can go to https://join.me/ then go to join meeting and type 361-099-548

OpenStudy (jazzyfa30):

what r u doing

OpenStudy (joppei):

i cant join, my internet here on the university is too slow

OpenStudy (joppei):

but i know my answer was wrong and i know why

OpenStudy (joppei):

if you look at the second problem: you sqrt a sqrt you multiply so (x²)² = x^4

OpenStudy (joppei):

so (4x^3*y)² = 16x^6*y^2 because you just sqrt 4x^3 which is 16x^6 (4² * (4^3)² and the y is just sqrt so you end up with 16x^6*y^2

OpenStudy (jazzyfa30):

ok

OpenStudy (anonymous):

@jazzyfa30

OpenStudy (jazzyfa30):

yeah sorry

OpenStudy (anonymous):

kk ..

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