Question

stuck on the delta Y of this equation.

Answer 1

for the delta Y to figure it out, i had

(x+deltaX)^2 - 1/x

but that is not right cause when i calculate it out, none of the answers are correct. I probably screwed the equation up when trying to imput the deriv of y= 1/x

Answer 2

\[\frac{dy}{dx}=-\frac{1}{x^2}\]

Answer 3

im assuming of course that you are taking the derivative of the function y?

Answer 4

\[y= \sqrt x~\to~\frac{dy}{dx}=\frac{1}{2\sqrt x}\]

Answer 5

let dx (or \(\triangle x\)) be evaluated at x= 3

\[y = \frac13,\to~\frac{1}{(3+1)}\]
\[\Delta y = \frac{1}{4}-\frac13\]

Answer 6

but thats just a guess, the instructions are hard to understand without the proper context