Question

**Correct Me :D [Work is Shown]
Jennie has a jar of 54 coins consisting of dimes and quarters. If she has a total of $11.10, how many dimes does she have?

10d + 25(54) + 25(-d) =1110
10d + 1350 + 25(-d) =1110
10d + 1350 - 25d = 1110
-15d + 1350 = 1110
Subtract 1350.
-15d = -240
Divided by -15
d = 16

Answer 1

d+q=54;
10d+25q=1110
d=16
q=38

Answer 2

Looks great to me, but make sure you establish before you start your work what you are letting your variables represent. It's not always clear. I would mention that you let d=number of dimes and 54-d=number of quarters, for example.

Answer 3

so you think she has 16 dimes and 54-16 = 38 quarters. let's see if that satisfies the problem

16*10 = 160
38*25 = 950
950+160 = 1110
your answer is correct.