Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

Answer 1

i really need help!

Answer 2

Pleas help me

Answer 3

the given line is 3x +y =7---> y = -3x +7
tell me what is the slope of that line?

Answer 4

6 right

Answer 5

@loser66 is it 6?

Answer 6

I 'm sorry, I step away for awhile. nope, the slope of that line is -3, so the slope of the line perpendicular to that line is 1/3

Answer 7

oh ok so you do the inverse @loser66

Answer 8

you have the form of the required line is y = 1/3 x + b. plug the point (6,-1) into that function to find b you have -1 = 1/3 *6 +b
--> b = -3. then plug back to y , so you have y = 1/3 x -3 is solution

Answer 9

@loser66 so the answer is the first choice?

Answer 10

@loser66 hello?

Answer 11

Yes it is the first choice

Answer 12

@MDoodler thank u! could you also, help me on another question? i really dont understand parralel and perpendicular lines