Question

The following system is solved by substitution. Which expression is substituted for z in the second and third equations?

x + 5y – z = 6
3x – y – 2z = 4
3x – 2y + 3z = 13

x + 5y + 6

x + 5y – 6

–x – 5y + 6

–x – 5y – 6

Answer 1

take first equation, solve for z

Answer 2

x + 5y – z = 6

Answer 3

alright//

Answer 4

to solve for z, u need to isolate z. so wat would u do to isolate it ?

Answer 5

add z on both sides?

Answer 6

perfect ! do that

Answer 7

alright...

Answer 8

wat do u get when u add z both sides

Answer 9

you should explain how you did on my last question cause i understood it better xD

Answer 10

last q you're making baby steps... this q u are running a marathon it seems, so...

Answer 11

x + 5y – z = 6
+z +z

Answer 12

x + 5y = 6+z

Answer 13

next what ?

Answer 14

i have no idea to be honest

Answer 15

ur goal is to isolate z, since 6 is attached to z, we subtract 6 both sides

Answer 16

x + 5y = 6+z
-6 -6

Answer 17

x+5y-6 = z

Answer 18

z = x+5y-6

Answer 19

ohhhhhhh okay