Part 2:
If you were an Algebra 1 instructor and were creating a test on factoring trinomials of the form ax2 + bx + c, what do you think would be the easiest way to create a trinomial that can be factored? Provide one unique example.

Question

Part 2: 
If you were an Algebra 1 instructor and were creating a test on factoring trinomials of the form ax2 + bx + c, what do you think would be the easiest way to create a trinomial that can be factored? Provide one unique example.

anonymous · Answer

so lets say  x^2-6 x+8  is factored to
(x-2)*(x-4)    

it is much easier if you were the instructered and piced 2 and 4 
for 
 (x-a)*(x-b)

and expanded to get x^2-6 x+8   than it is for the student to factor x^2-6 x+8  and get
(x-2)*(x-4)
as answer

anonymous · Answer

*instructor and picked

anonymous · Answer

Although there are many different ways to factor  a trinomial, I would say the easiest  is in the form of $$x^2 + 6x + 8 $$. This form allows the student to get their feet wet in factoring before they move into other factoring methods such as trial and error and Grouping. It also allows them to see why they have been studying FOIL. Normally the student learns FOIL and then they get into Factoring trinomials. I would even say that $$x^2 + 6x + 8 $$ is an easier form than 
$$x^2 - 6x + 8 $$ or
or
$$x^2 + 6x - 8 $$ or
$$x^2 - 6x - 8 $$

to start teaching about trinomials.