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Mathematics 13 Online
OpenStudy (anonymous):

Factor: 3x^3+12x^2+3x+12

OpenStudy (anonymous):

We could start by factoring out a 3, since all the terms have one: \[3(x^3 +4x^2 +x +4)\] which should make this a little easier to factor.

OpenStudy (dan815):

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OpenStudy (anonymous):

Verify that\[3 (x+4) \left(x^2+1\right) \]can be a result.

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