what is the equation of the line that passes through the points (3,2)and has a slope of 4
are you familiar with y=mx+c
Yes but I get confused
alright. do you know what m represents?
Slope
aren't we given the slope though?
so automatically we can say y=4x+c
follow?
Yes but then C is what?
well 'c' is the y-intercept of the graph right?
what other information have you been given?
@chris00 cant she use \[y - y_{1}=m(x-x_{1})\] and just solve for y?
you need two points though...your only given one. and that only gives the slope which we are have already been given in the question
The other information are the answers
\[y - 2 = 4(x-3)\] solve for y you get a \[y = mx + b\] and you will have your equation
i never learnt it that way. when you know y=4x+c substitute (3,2) into x any y 2=4(3)+c c=-10 therefore your equation of your line is y=4x-10
Which are y=4x-1 y=4x-5 y=4x-10 y=4x+1
That way is way easier thank you
@chris00 yea that works too did not mean to interrupt you :)
my way grasps the concept of a line visually. whereas a general formula is just a mere plug and chug. but no thats fine to interrupt. more ways the better
graph it to check if (3,2) lies on the line though. so you can be sure that the line is correct
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