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Use the law of cosines to find the value of cos theta. Round your answer to two decimal places.
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Do you know the law of cosines?
no idea i just left it alone and moved on thanks anyways
For any triangle with angles A,B,C, and with opposite sides (to these angles) respectively a,b,c \[c^2=a^2+b^2-2ab\cos C\]
so if you look are your picture Which side do you think is side c ?
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|dw:1438402876970:dw| the side c, is the side opposite to the angle theta (angle C) so \[(5.7)^2 = (9.8)^2+(10.2^)2-2(9.8)(10.2)\cos(\theta)\]
*\[(5.7)^2 = (9.8)^2+(10.2)^2-2(9.8)(10.2)\cos(\theta)\]
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