Question

find inverse of y=x^2-1??

Answer 1

Swap and solve! What's holding you back?

Answer 2

\[y \pm \sqrt{x-1}\]

Answer 3

is that right?

Answer 4

y(x)=\[\pm \sqrt{y+1}\]

Answer 5

thats not in my options

Answer 6

idk if mine is right /:

Answer 7

theres one like that but instead its an x+1

Answer 8

yes, should include \(x+1\)

Answer 9

ah ok Thanx!!

Answer 10

\[y=x^2-1\]
\[x=y^2-1\]
\[x+1=y^2\]
\[\pm\sqrt{x+1}=y\]

Answer 11

Substitute it in to ceck i.e ... sub in \[(\sqrt{x+1)}^2-1\] and simplify

Answer 12

yeah thats the one i have in my options