Question

Solve the following roots. Please explain!

Answer 1

\[\sqrt[3]{64}\]

Answer 2

@HopefullySuccessful ... reply pl

Answer 3

@shkrina Sorry, I had to go somewhere. Is the answer 811?

Answer 4

hehehe

Answer 5

I can't really understand her writing... :/

Answer 6

well, this is what I read as the original root => \(\huge \sqrt[3]{64}\)

Answer 7

you're just finding the cube root of 64

since 4^3 = 4*4*4 = 64, this means

\[\large \sqrt[3]{64} = 4\]

Answer 8

or you can think of it like this

\[\large \sqrt[3]{64} = \sqrt[3]{4^3}\]

\[\large \sqrt[3]{64} = 4\]

Answer 9

Okay so I just find whatever goes into the bigger number the amount of times of whatever the smaller number is?

Answer 10

yes you try to write that number as a product of 3 numbers (which are the same number)

Answer 11

Okay, I see now. How about this one? \[(2\sqrt{18}) (3\sqrt{8})\]

Answer 12

multiply the outer numbers 2 and 3 to get 2*3 = 6

Answer 13

then multiply the numbers in the square roots: 18*8 = 144

Answer 14

so you should have \[\large 6*\sqrt{144} = ???\]

Answer 15

24!

Answer 16

no

Answer 17

the square root of 144 isn't 4

Answer 18

Oh wait a minute! i did that totally wrong.

Answer 19

11

Answer 20

\[\large 6*\sqrt{144} = 6*12 = 72\]

Answer 21

Ohh! I'm getting this now. Okay, last one I promise. \[\sqrt{50} \div \]

Answer 22

something is missing

Answer 23

5

Answer 24

Sorry about that

Answer 25

\[\large \sqrt{50} = \sqrt{25*2}\]


\[\large \sqrt{50} = \sqrt{25}*\sqrt{2}\]


\[\large \sqrt{50} = \sqrt{5^{2}}*\sqrt{2}\]


\[\large \sqrt{50} = 5\sqrt{2}\]

Answer 26

so

\[\large \sqrt{50} \div 5\]

turns into

\[\large 5\sqrt{2} \div 5\]

and the 5's cancel giving you this

\[\large \sqrt{2}\]



So this means \[\large \sqrt{50} \div 5 = \sqrt{2}\]