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OpenStudy (anonymous):
find the square-root of 60 times the square-root of 105. HELP!!!!!!!!!!!
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OpenStudy (anonymous):
multiply whatever is inside of the square root
OpenStudy (anonymous):
so it would be .... √6300
OpenStudy (anonymous):
? BUT YOU CAN'T FIND THE SQUARE ROOT OF 105 OR 60
OpenStudy (anonymous):
then simplify
OpenStudy (anonymous):
mulitply what ever is inside first
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OpenStudy (anonymous):
when you multiply it would √6300
OpenStudy (anonymous):
then simplify it
OpenStudy (anonymous):
the square root of 60 is a decimal: 7.7
the square root of 105 is also a decimal: 10.2
7.7 * 10.2= 78.5
OpenStudy (anonymous):
or never mind you cant simplify
OpenStudy (anonymous):
nooo you would first multiply 60 and 105
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OpenStudy (anonymous):
so then i would have to find the square root of 6300.
So... a decimal? (79.4) ?
OpenStudy (anonymous):
it would be √6300
OpenStudy (anonymous):
then simplify
OpenStudy (anonymous):
so it would be 30√7
OpenStudy (anonymous):
how did you do that? could you explain how you simplified that?
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OpenStudy (anonymous):
i just typed the problem in wolfram alpha but the way you would do it would be to use a factor tre and take out whatever is in common so....
OpenStudy (anonymous):
oh, i get it. thank you so much!
OpenStudy (anonymous):
youre welcome!
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