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Mathematics 16 Online
OpenStudy (anonymous):

Can somebody simplify this?

OpenStudy (anonymous):

\[f(\frac{ 2 }{ 3 }a)= (\frac{ 2 }{ 3 }a)^3- a(\frac{ 2}{ 3 }a)^2 \] where a>0. Solve in terms of a

OpenStudy (whpalmer4):

What is \[(\frac{2}{3}a)^3\]What is \[(\frac{2}{3}a)^2\]

OpenStudy (anonymous):

(8a/27) and (4a/9), respectively

OpenStudy (anonymous):

ergo, (8a/27)-a*(12a/27)

OpenStudy (anonymous):

and then my answer deviates from the book

OpenStudy (whpalmer4):

\[(\frac{2}{3}a)^3 = \frac{2^3}{3^3}a^3 = \frac{8}{27}a^3\] \[(\frac{2}{3}a)^2 = \frac{2^2}{3^2}a^2 = \frac{4}{9}a^2\] \[(\frac{2}{3}a)^3 - a(\frac{2}{3}a)^2 = \frac{8}{27}a^3 - a\frac{4}{9}a^2 = \frac{8}{27}a^3-\frac{4}{9}a^3\]\[=\frac{8}{27}a^3-\frac{12}{27}a^3 =-\frac{4}{27}a^3 \]

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