HELP finding partial fraction decomposition? (PIC INCLUDED)
@satellite73
@Hero help me pleaseee??
@ash2326 can you help me?
We have \[\frac{5}{3x^2-x-2}\] Can you factor the denominator?
yes i got (x-3)(x+2)
Check again, there is some mistake. Try multiplying this, are you getting the denominator?
i factored denominator
\[(x-3)(x+2)=x^2-x-6\ne 3x^2-x-2\]
oh so what does tht factor into then??
\[3x^2-x-2\] \[3x^2-3x+2x-2\] \[3x(x-1)+2(x-1)\] Can you find now?
ok so thats the answer for denomiator?
its a partial fraction denominator i dont know what that is
It's to be factored, just one more step
i meant partial fracton decompostion
We'll work on that, could you write the two factors
what you just put for that equation?
I suppose those are not factors, please do one more step and write the two factors
(x-1)(x-1) ??
Have you studied factoring? @idreamofpink
yes i have but not partial fractoin decomposition. im just at a lost.
im tryna figure out what the answer is and i just have no clue.
We'll work on that, please just factor this \[3x^2-x-2\]
i honestly don know how that can be factored.
\[3x^2-x-2\] Can you write factors of -6? which add to -1
-3 and 2
Good so \[3x^2-3x+2x-2\] Can you take common out of the first two and last two terms?
I'll brb
yes 1
So Did you work it out?
isnt gona be same answer
i need step by step i dont know what to do. -_-
@ash2326 ?
So you have \(\large 3x^2-3x+2x-2\) which = \(\large 3x^2 -x - 2\) right ?
Factor out like terms and simplify by grouping\[\large (\color{green}{3x}^2 - 3x )+(\color{blue}2x-2) \] can you tellme what you get when you factor out like terms from these two groups?
yewa i already skipped that question tho.. but thanks anyway
Why skip it when we can help you solve it? :)
i already skipped it before you replied but can you help me with another question?
Well, if you have a calc book you can look up partial fractions in your index...
I can try, but i have to go soon. I'll start you off.
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