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Mathematics 17 Online
OpenStudy (anonymous):

HELP finding partial fraction decomposition? (PIC INCLUDED)

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@Hero help me pleaseee??

OpenStudy (anonymous):

@ash2326 can you help me?

OpenStudy (ash2326):

We have \[\frac{5}{3x^2-x-2}\] Can you factor the denominator?

OpenStudy (anonymous):

yes i got (x-3)(x+2)

OpenStudy (ash2326):

Check again, there is some mistake. Try multiplying this, are you getting the denominator?

OpenStudy (anonymous):

i factored denominator

OpenStudy (ash2326):

\[(x-3)(x+2)=x^2-x-6\ne 3x^2-x-2\]

OpenStudy (anonymous):

oh so what does tht factor into then??

OpenStudy (ash2326):

\[3x^2-x-2\] \[3x^2-3x+2x-2\] \[3x(x-1)+2(x-1)\] Can you find now?

OpenStudy (anonymous):

ok so thats the answer for denomiator?

OpenStudy (anonymous):

its a partial fraction denominator i dont know what that is

OpenStudy (ash2326):

It's to be factored, just one more step

OpenStudy (anonymous):

i meant partial fracton decompostion

OpenStudy (ash2326):

We'll work on that, could you write the two factors

OpenStudy (anonymous):

what you just put for that equation?

OpenStudy (ash2326):

I suppose those are not factors, please do one more step and write the two factors

OpenStudy (anonymous):

(x-1)(x-1) ??

OpenStudy (ash2326):

Have you studied factoring? @idreamofpink

OpenStudy (anonymous):

yes i have but not partial fractoin decomposition. im just at a lost.

OpenStudy (anonymous):

im tryna figure out what the answer is and i just have no clue.

OpenStudy (ash2326):

We'll work on that, please just factor this \[3x^2-x-2\]

OpenStudy (anonymous):

i honestly don know how that can be factored.

OpenStudy (ash2326):

\[3x^2-x-2\] Can you write factors of -6? which add to -1

OpenStudy (anonymous):

-3 and 2

OpenStudy (ash2326):

Good so \[3x^2-3x+2x-2\] Can you take common out of the first two and last two terms?

OpenStudy (ash2326):

I'll brb

OpenStudy (anonymous):

yes 1

OpenStudy (ash2326):

So Did you work it out?

OpenStudy (anonymous):

isnt gona be same answer

OpenStudy (anonymous):

i need step by step i dont know what to do. -_-

OpenStudy (anonymous):

@ash2326 ?

OpenStudy (jhannybean):

So you have \(\large 3x^2-3x+2x-2\) which = \(\large 3x^2 -x - 2\) right ?

OpenStudy (jhannybean):

Factor out like terms and simplify by grouping\[\large (\color{green}{3x}^2 - 3x )+(\color{blue}2x-2) \] can you tellme what you get when you factor out like terms from these two groups?

OpenStudy (anonymous):

yewa i already skipped that question tho.. but thanks anyway

OpenStudy (jhannybean):

Why skip it when we can help you solve it? :)

OpenStudy (anonymous):

i already skipped it before you replied but can you help me with another question?

OpenStudy (jhannybean):

Well, if you have a calc book you can look up partial fractions in your index...

OpenStudy (jhannybean):

I can try, but i have to go soon. I'll start you off.

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