4x^3+12x^2+3x+9
what is the thing between x and 3
\[4x ^{3}+12x ^{2}+3x+9\]
I would like to know HOW to do this, suggestions?
Simplifying 4x4 + -12x2 + 9 = 0 Reorder the terms: 9 + -12x2 + 4x4 = 0 Solving 9 + -12x2 + 4x4 = 0 Solving for variable 'x'. Factor a trinomial. (3 + -2x2)(3 + -2x2) = 0 Subproblem 1Set the factor '(3 + -2x2)' equal to zero and attempt to solve: Simplifying 3 + -2x2 = 0 Solving 3 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2x2 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2x2 = 0 + -3 -2x2 = 0 + -3 Combine like terms: 0 + -3 = -3 -2x2 = -3 Divide each side by '-2'. x2 = 1.5 Simplifying x2 = 1.5 Take the square root of each side: x = {-1.224744871, 1.224744871} Subproblem 2Set the factor '(3 + -2x2)' equal to zero and attempt to solve: Simplifying 3 + -2x2 = 0 Solving 3 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2x2 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2x2 = 0 + -3 -2x2 = 0 + -3 Combine like terms: 0 + -3 = -3 -2x2 = -3 Divide each side by '-2'. x2 = 1.5 Simplifying x2 = 1.5 Take the square root of each side: x = {-1.224744871, 1.224744871}Solutionx = {-1.224744871, 1.224744871, -1.224744871, 1.224744871}
64+144+3+9+=217
how would you simplify it instead of solving it?
you would do as exactly as she did lovey
@lovepink97
would that be the same as factoring?
\[4x^3+12X^2+3x+9 = (x+3)(4x^2+3)\]
tnx!
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