Question

Use a(t) = -9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.)

A baseball is thrown upward from a height of 3 meters with an initial velocity of 9 meters per second. Determine its maximum height. (Round your answer to two decimal places.)

Answer 1

let a(t) = g= 9.8m/s^2
X1= 3m
viy = 9m/s
vfy = 0m/s at max height

vf^2y = Vf^2y + 2gXo

Xo = vf^2 -vi^2/2g
Xo = 0-(9m/s)^2/2(-9.8m/s^2)
Xo = 4.13m.. add the X1 (+3)
= 7.13m

I think that's the maximum height...