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Mathematics 14 Online
OpenStudy (anonymous):

State the number of possible positive and negative zeros for each function. f(x) = 3x^4 + 20x^2 -32 so confused, what exact;y am I doin?

OpenStudy (anonymous):

any ideas @ChrisJP

OpenStudy (anonymous):

i was afk srry

OpenStudy (anonymous):

im not too sure, but my suggestion would be to factor the right side of the equation then to enter it into (y=) on a TI calc.

OpenStudy (anonymous):

but thats probly a horrible suggestion

OpenStudy (jdoe0001):

have you done yet Descartes Law of Signs?

OpenStudy (jdoe0001):

@amyamanda http://www.youtube.com/watch?v=5YAmwfT3Esc

OpenStudy (anonymous):

...f(x) = 3x^4 + 20x^2 -32 --- here in f(x) the sign changes only once from +ve to -ve... so there is only one +ve roots.. Then in , f(-x) = 3x^4 + 20x^2 -32 ..... too the sign changes only once. So there is only one -ve root

OpenStudy (anonymous):

got it thanks @jdoe0001

OpenStudy (jdoe0001):

yw

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