Imagine that you are on Mars, and you are swinging a pocket watch back and forth. You time the period of this simple pendulum to be 2.6 seconds, and you measure the chain on the pocket watch to be 63 centimeters. Using this information, figure out what the gravity of Mars is. ANY ONE CAN HELP?

A. 4.2 meters/second²
B. 2.7 meters/second²
C. 3.1 meters/second²
D. 3.7 meters/second²

Question

Imagine that you are on Mars, and you are swinging a pocket watch back and forth. You time the period of this simple pendulum to be 2.6 seconds, and you measure the chain on the pocket watch to be 63 centimeters. Using this information, figure out what the gravity of Mars is. ANY ONE CAN HELP? 


A. 4.2 meters/second² 
B. 2.7 meters/second² 
C. 3.1 meters/second² 
D. 3.7 meters/second²

souvik · Answer

$$T=2\pi \sqrt{L/g}$$
you know T and L find g..

theeric · Answer

souvik provide the equation that describes simple pendulum properties.
And souvik gave you a hint afterwards. For further clarification, $T \text{ is the period and } L \text{ is the length of the pendulum. } \g\text{ is the gravitational acceleration, specific to your problem (on Mars)}$

theeric · Answer

Given souvik's response and mine, you have all the tools you need to calculate the answer! Good luck, you can do it!