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consider the following: f(x) = tan((pi/x)/2) find the x-values at which f is not continuous. (From the calculatorI know that at -3,-1,1,3, it shows up as error, but when I put them as the answer, it shows up as incorrect)
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if allowed, try graphing it, check the vertical asymptotes
well the first way to approach this is think when is tan undefined because there is where it will not be continuous. we know that as pi/2 and -pi/2 from [0,pi) so set it up as such (pi/x)/2= pi/2 and (pi/x)/2=-pi/2
-3 and 3 wouldn't give you the answer either pi/3/2 = pi/6
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