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True or False.
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If \[\int\limits_{0}^{2}f(x)dx = 6\] then \[\int\limits_{0}^{4}f(x)dx =12\]
@amistre64
not in general
\[\int\limits_{0}^{2}f(x)dx = \int\limits_{0}^{2}f(t)dt\]
in general, the integration of 2 functions are not equal ....
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\[\int\limits_{-1}^{1}f(x)dx = 2\int\limits_{0}^{1}f(x)d\]
only if a function is even i beleive
The question only has that as a statement with the option of either true or false. I believe it is false because they haven't stated it as even.
\[\int_{-1}^{1}x~dx=\frac12(1)^2-\frac12(-1)^2=0\]
\[\int_{0}^{1}x~dx=\frac12(1)^2-\frac12(0)^2=\frac12\] and 2*1/2 not equal 0
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Okay, thank you for that. It really helped to look at it that way.
when in doubt, run a simple test :)
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