Question

Evaluate cot(sec^-1 (2/X))??

Answer 1

The drawing below shows angle theta with
\[\sec \theta=\frac{2}{x}\]

by the theorem of Pythagoras the length of the third side of the triangle is\[\sqrt{4-x ^{2}}\]
Now can you find the cotangent of theta?

Answer 2

Hint: In a right angled triangle the cotangent of an angle is:\[Cotangent=\frac{adjacent}{opposite}\]

Answer 3

@coolgirl3517 In the drawing that I posted above, what is the side adjacent to angle theta?

Answer 4

Would the answer be X divided by square root of 4-X square?

Answer 5

Yes, that is the correct answer :)

Answer 6

Thank you!!

Answer 7

You're welcome :)