Find a ⋅ b. a = 8i + 6j, b = 4i + 5j
You are to just mutiply them.. Do you know about FOIL??
yes but the answer choices are numbers! i know i as an imaginary number but j as a variable and i think they are both variables in the problem.
If i is an imaginary here then : \[-32 + 64i.j + 30j^2\]
its not............... the answer is a digit....... idk what it is
no its somethign to do with dot products and vectors
\[a \color{red} {\cdot} b = |ab|\cos(\theta)\]
Or simply mutiply i coefficient with i and j with j.. \[a \cdot b = 8 \times 4 + 6 \times 5 \implies \color{green}{32 + 30} = ??\]
yes!!! thank you!!!
Got it right or not?
yep:)
now do you know if i am multiplying v *w and v = <3, -8, -3>; w = <-4, -2, -6> how do i solve this?
like do i multiply v1*w1 + v2w2+v3w3?
Is it \(v \cdot w\) or \(v \times w\) ??
v⋅w
Yes just multiply the corresponding elemets there..
Yes, as you are saying go like that... v1*w1 + v2......... and so on..
thank you:)
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