Question

differentiate
tan^-1((a+btanx)/(b-atanx))

Answer 1

try and put b/a = tan (alpha)
then
(a+btanx)/(b-atanx) will be of the form tan (...+...)

Answer 2

oh

Answer 3

let me try by using ur method

Answer 4

@hartnn -:/

Answer 5

tan^-1{(a/b+tanx)/(1-a/btanx)}
lets take \[a/b=\tan \alpha \]
tan^-1[{tan(alpha)+tanx}/1-tanx*tan(alpha)}]
=tan^-1[tan(x+alpha)
=x+alpha

Answer 6

oh, it was a/b = tan alpha , not b/a :P

Answer 7

oh :OOO is there any other method to solve it ???????

Answer 8

i thought u can only substitute x variable only

Answer 9

i feel this is the easiest :)
here we replaced one constant, (a/b) with other ...

Answer 10

oh :O

Answer 11

@souvik @hartnn -why allpha not tanx ???????

Answer 12

alpha*

Answer 13

tan x ? ''x'' is a variable,
whereas a and b are constants
we can replace a constant by a constant, and variable by a variable
not a constant by a variable and....

Answer 14

oh :OOO