Question

suppose the function below was expressed in standard form Y=ax^2+bx+c. what is the value of a with the vertex -3,-2

Answer 1

if we were to complete the square:

y = ax^2 + bx + c

y/a = x^2 + b/a x + c/a

y/a = (x^2 + b/a x +b^2/4a^2) - b^2/4a^2 + 4ac/4a^2

y/a = (x - (-b/2a))^2 - (b^2-4ac)/4a^2

y = a(x - (-b/2a))^2 - (b^2-4ac)/4a

Answer 2

thanks.!

Answer 3

youre welcome

in this format we can relate the vertex (p,q) as:

y = a(x-p)^2 + q which should give us a means of working out the finer details