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Mathematics 19 Online
OpenStudy (anonymous):

a^3+125b^3

OpenStudy (anonymous):

125 cube .... is 5 ... apply the formulare

OpenStudy (anonymous):

give me the example plsss

OpenStudy (souvik):

a^3+125b^3 =a^3+(5b)^3

OpenStudy (anonymous):

if i'm not mistaken, sum of cubes is \[\huge a^3 + b^3 = (a+b)(a^2 - ab + b^2)\]

OpenStudy (anonymous):

answer pls

OpenStudy (souvik):

put 5b ni place of b

OpenStudy (anonymous):

the revers in the answer

OpenStudy (souvik):

(a+5b){a^2-a*5b+(5b)^2}

OpenStudy (anonymous):

a^3+(5b)^3

OpenStudy (anonymous):

is that the answeR?

OpenStudy (anonymous):

no! so pls solve it for me

OpenStudy (anonymous):

plssss

OpenStudy (mayankdevnani):

yeah!! sorry... @souvik i deleted it

OpenStudy (anonymous):

ok thanks guisss im Doneee

OpenStudy (anonymous):

apply this formula \[a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})\] \[a^{3}+125=a^{3}+5^{3}=(a+5)(a^{2}-a.5+5^{2})=(a+5)(a^{2}-5a+25)\]

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